Pomelo Lee workspace

#!/usr/bin/perl -w
$maxprimes=100;
$value=1;
$count=0;
while($count <$maxprimes){
	$value++;
	$composite=0;
OUTER: for($i=2;$i<$value;$i++){
		for($j=$i;$j<$value;$j++){
		  if(($j*$i)==$value){
			$composite=1;
			last OUTER;
  			}
		}
	}
	if(!$composite){
		$count++;
		print "$value is prime count is $count \n";}
}

package com.liyz.num.test;
public class PrimeNum {
	public static void main(String[] args) {
		long start=System.currentTimeMillis();
		primeMehtodTwo(100);
		long end=System.currentTimeMillis();
		System.out.println("use time is " +(end-start)+" ms");
	}
	//效率太差,取的质数越多，比较的次数也越多,效率也越低
	public static void primeMehtodOne( int number){
		int num=number;
		int value=1;
		int count=0;
		boolean composite;
		while (count<num){
			value++;
			composite=false;
			for(int i=2;i<value;i++){
				for(int j=i;j<value;j++){
					if((j*i)==value){
						composite=true;
						break;
					}
				}
			}
			if(!composite){
				count++;
				System.out.println(value+" is prime!");
			}
		}
	}
	//感觉好多了,更好的算法没有去研究过
	public static void primeMehtodTwo(int number){
		int count=0;
		int fg=1;
		int num=number;
 
		for( int i=2;count<num;i++){
			double k=Math.sqrt(i+1);
			for(int j=2;j<=k;j++){
				if((i%j)==0){
					fg=0;
					break;
				}
			}
			if(fg==1){
				System.out.println(i+" is prime!");
				count++;
			}
			fg=1;
		}
	}
	}